7. Reverse Integer

class Solution {
    public int reverse(int x) {
        long xx = (long)x;
        if (xx == 0) return 0;
        int flag;
        if (xx > 0){
            flag = 1;
        }
        else{
            flag = -1;
        }

        xx = Math.abs(xx);

        long ans = 0;
        while (xx > 0){
            long cur = xx % 10;
            ans = ans * 10 + cur;
            xx /= 10;
        }

        ans *= flag;

        if (ans > Integer.MAX_VALUE || ans < Integer.MIN_VALUE) return 0;
        return (int)ans;
    }
}

results for ""

    No results matching ""