#
.
_9_
/ \
3 2
/ \ / \
4 1 # 6
/ \ / \ / \
# # # # # #
For example, the above binary tree can be serialized to the string"9,3,4,#,#,1,#,#,2,#,6,#,#"
, where#
represents a null node.
Given a string of comma separated values, verify whether it is a correct preorder traversal serialization of a binary tree. Find an algorithm without reconstructing the tree.
Each comma separated value in the string must be either an integer or a character'#'
representingnull
pointer.
You may assume that the input format is always valid, for example it could never contain two consecutive commas such as"1,,3"
.
Example 1:"9,3,4,#,#,1,#,#,2,#,6,#,#"
Returntrue
Example 2:"1,#"
Returnfalse
Example 3:"9,#,#,1"
Returnfalse
class Solution {
public boolean isValidSerialization(String preorder) {
if (preorder == null || preorder.length() == 0) return true;
int diff = 1;
for (String str : preorder.split(",")){
if (--diff < 0) return false;
if (!str.equals("#")) diff += 2;
}
return diff == 0;
}
}
class Solution {
public boolean isValidSerialization(String preorder) {
String[] strs = preorder.split(",");
return dfs(strs, 0) == strs.length;
}
private int dfs(String[] strs, int index){
if (index >= strs.length) return -1;
if (strs[index].equals("#")) return 1;
int leftLen = dfs(strs, index + 1);
if (leftLen == -1) return -1;
int rightLen = dfs(strs, index + 1 + leftLen);
if (rightLen == -1) return -1;
return 1 + leftLen + rightLen;
}
}