Follow up for problem "Populating Next Right Pointers in Each Node".
What if the given tree could be any binary tree? Would your previous solution still work?
Note:
For example,
Given the following binary tree,
1
/ \
2 3
/ \ \
4 5 7
After calling your function, the tree should look like:
1 -
>
NULL
/ \
2 -
>
3 -
>
NULL
/ \ \
4-
>
5 -
>
7 -
>
NULL
tag: binary tree
/**
* Definition for binary tree with next pointer.
* public class TreeLinkNode {
* int val;
* TreeLinkNode left, right, next;
* TreeLinkNode(int x) { val = x; }
* }
*/
public class Solution {
public void connect(TreeLinkNode root) {
TreeLinkNode head = null;
TreeLinkNode prev = null;
TreeLinkNode cur = root;
while (cur != null){
// from current level, connect next level
while (cur != null){
if (cur.left != null){
if (prev != null){
prev.next = cur.left;
}
else{
head = cur.left;
}
prev = cur.left;
}
if (cur.right != null){
if (prev != null){
prev.next = cur.right;
}
else{
head = cur.right;
}
prev = cur.right;
}
cur = cur.next;
}
// move to next level
cur = head;
head = null;
prev = null;
}
}
}